Optimal. Leaf size=201 \[ -\frac {e p \log \left (d+e x^2\right )}{2 f (e f-d g)}+\frac {\log \left (c \left (d+e x^2\right )^p\right )}{2 f \left (f+g x^2\right )}+\frac {\log \left (-\frac {e x^2}{d}\right ) \log \left (c \left (d+e x^2\right )^p\right )}{2 f^2}+\frac {e p \log \left (f+g x^2\right )}{2 f (e f-d g)}-\frac {\log \left (c \left (d+e x^2\right )^p\right ) \log \left (\frac {e \left (f+g x^2\right )}{e f-d g}\right )}{2 f^2}-\frac {p \text {Li}_2\left (-\frac {g \left (d+e x^2\right )}{e f-d g}\right )}{2 f^2}+\frac {p \text {Li}_2\left (1+\frac {e x^2}{d}\right )}{2 f^2} \]
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Rubi [A]
time = 0.19, antiderivative size = 201, normalized size of antiderivative = 1.00, number of steps
used = 12, number of rules used = 10, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {2525, 46,
2463, 2441, 2352, 2442, 36, 31, 2440, 2438} \begin {gather*} -\frac {p \text {PolyLog}\left (2,-\frac {g \left (d+e x^2\right )}{e f-d g}\right )}{2 f^2}+\frac {p \text {PolyLog}\left (2,\frac {e x^2}{d}+1\right )}{2 f^2}-\frac {\log \left (c \left (d+e x^2\right )^p\right ) \log \left (\frac {e \left (f+g x^2\right )}{e f-d g}\right )}{2 f^2}+\frac {\log \left (-\frac {e x^2}{d}\right ) \log \left (c \left (d+e x^2\right )^p\right )}{2 f^2}+\frac {\log \left (c \left (d+e x^2\right )^p\right )}{2 f \left (f+g x^2\right )}-\frac {e p \log \left (d+e x^2\right )}{2 f (e f-d g)}+\frac {e p \log \left (f+g x^2\right )}{2 f (e f-d g)} \end {gather*}
Antiderivative was successfully verified.
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Rule 31
Rule 36
Rule 46
Rule 2352
Rule 2438
Rule 2440
Rule 2441
Rule 2442
Rule 2463
Rule 2525
Rubi steps
\begin {align*} \int \frac {\log \left (c \left (d+e x^2\right )^p\right )}{x \left (f+g x^2\right )^2} \, dx &=\frac {1}{2} \text {Subst}\left (\int \frac {\log \left (c (d+e x)^p\right )}{x (f+g x)^2} \, dx,x,x^2\right )\\ &=\frac {1}{2} \text {Subst}\left (\int \left (\frac {\log \left (c (d+e x)^p\right )}{f^2 x}-\frac {g \log \left (c (d+e x)^p\right )}{f (f+g x)^2}-\frac {g \log \left (c (d+e x)^p\right )}{f^2 (f+g x)}\right ) \, dx,x,x^2\right )\\ &=\frac {\text {Subst}\left (\int \frac {\log \left (c (d+e x)^p\right )}{x} \, dx,x,x^2\right )}{2 f^2}-\frac {g \text {Subst}\left (\int \frac {\log \left (c (d+e x)^p\right )}{f+g x} \, dx,x,x^2\right )}{2 f^2}-\frac {g \text {Subst}\left (\int \frac {\log \left (c (d+e x)^p\right )}{(f+g x)^2} \, dx,x,x^2\right )}{2 f}\\ &=\frac {\log \left (c \left (d+e x^2\right )^p\right )}{2 f \left (f+g x^2\right )}+\frac {\log \left (-\frac {e x^2}{d}\right ) \log \left (c \left (d+e x^2\right )^p\right )}{2 f^2}-\frac {\log \left (c \left (d+e x^2\right )^p\right ) \log \left (\frac {e \left (f+g x^2\right )}{e f-d g}\right )}{2 f^2}-\frac {(e p) \text {Subst}\left (\int \frac {\log \left (-\frac {e x}{d}\right )}{d+e x} \, dx,x,x^2\right )}{2 f^2}+\frac {(e p) \text {Subst}\left (\int \frac {\log \left (\frac {e (f+g x)}{e f-d g}\right )}{d+e x} \, dx,x,x^2\right )}{2 f^2}-\frac {(e p) \text {Subst}\left (\int \frac {1}{(d+e x) (f+g x)} \, dx,x,x^2\right )}{2 f}\\ &=\frac {\log \left (c \left (d+e x^2\right )^p\right )}{2 f \left (f+g x^2\right )}+\frac {\log \left (-\frac {e x^2}{d}\right ) \log \left (c \left (d+e x^2\right )^p\right )}{2 f^2}-\frac {\log \left (c \left (d+e x^2\right )^p\right ) \log \left (\frac {e \left (f+g x^2\right )}{e f-d g}\right )}{2 f^2}+\frac {p \text {Li}_2\left (1+\frac {e x^2}{d}\right )}{2 f^2}+\frac {p \text {Subst}\left (\int \frac {\log \left (1+\frac {g x}{e f-d g}\right )}{x} \, dx,x,d+e x^2\right )}{2 f^2}-\frac {\left (e^2 p\right ) \text {Subst}\left (\int \frac {1}{d+e x} \, dx,x,x^2\right )}{2 f (e f-d g)}+\frac {(e g p) \text {Subst}\left (\int \frac {1}{f+g x} \, dx,x,x^2\right )}{2 f (e f-d g)}\\ &=-\frac {e p \log \left (d+e x^2\right )}{2 f (e f-d g)}+\frac {\log \left (c \left (d+e x^2\right )^p\right )}{2 f \left (f+g x^2\right )}+\frac {\log \left (-\frac {e x^2}{d}\right ) \log \left (c \left (d+e x^2\right )^p\right )}{2 f^2}+\frac {e p \log \left (f+g x^2\right )}{2 f (e f-d g)}-\frac {\log \left (c \left (d+e x^2\right )^p\right ) \log \left (\frac {e \left (f+g x^2\right )}{e f-d g}\right )}{2 f^2}-\frac {p \text {Li}_2\left (-\frac {g \left (d+e x^2\right )}{e f-d g}\right )}{2 f^2}+\frac {p \text {Li}_2\left (1+\frac {e x^2}{d}\right )}{2 f^2}\\ \end {align*}
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Mathematica [A]
time = 0.07, size = 170, normalized size = 0.85 \begin {gather*} \frac {\frac {e f p \log \left (d+e x^2\right )}{-e f+d g}+\frac {f \log \left (c \left (d+e x^2\right )^p\right )}{f+g x^2}+\log \left (-\frac {e x^2}{d}\right ) \log \left (c \left (d+e x^2\right )^p\right )+\frac {e f p \log \left (f+g x^2\right )}{e f-d g}-\log \left (c \left (d+e x^2\right )^p\right ) \log \left (\frac {e \left (f+g x^2\right )}{e f-d g}\right )-p \text {Li}_2\left (\frac {g \left (d+e x^2\right )}{-e f+d g}\right )+p \text {Li}_2\left (1+\frac {e x^2}{d}\right )}{2 f^2} \end {gather*}
Antiderivative was successfully verified.
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Maple [C] Result contains higher order function than in optimal. Order 9 vs. order
4.
time = 0.46, size = 984, normalized size = 4.90
method | result | size |
risch | \(\text {Expression too large to display}\) | \(984\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.54, size = 208, normalized size = 1.03 \begin {gather*} -\frac {1}{2} \, p {\left (\frac {{\left (2 \, \log \left (\frac {x^{2} e}{d} + 1\right ) \log \left (x\right ) + {\rm Li}_2\left (-\frac {x^{2} e}{d}\right )\right )} e^{\left (-1\right )}}{f^{2}} - \frac {{\left (\log \left (g x^{2} + f\right ) \log \left (\frac {g x^{2} e + f e}{d g - f e} + 1\right ) + {\rm Li}_2\left (-\frac {g x^{2} e + f e}{d g - f e}\right )\right )} e^{\left (-1\right )}}{f^{2}} + \frac {\log \left (g x^{2} + f\right )}{d f g - f^{2} e} - \frac {\log \left (x^{2} e + d\right )}{d f g - f^{2} e}\right )} e + \frac {1}{2} \, {\left (\frac {1}{f g x^{2} + f^{2}} - \frac {\log \left (g x^{2} + f\right )}{f^{2}} + \frac {\log \left (x^{2}\right )}{f^{2}}\right )} \log \left ({\left (x^{2} e + d\right )}^{p} c\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {\ln \left (c\,{\left (e\,x^2+d\right )}^p\right )}{x\,{\left (g\,x^2+f\right )}^2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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